design of rectangular tanks pdf to excel

Minimum steel % For mild steel 100 As / b d = 100 x 0.85 / 250 = 0.34 For HYSD steel, Fe415 grade 100 As / b d = 100 x 0.85 / 415 = 0.205 For HYSD steel, Fe500 grade 100 As / b d = 100 x 0.85 / 500 = 0.17įor checking development length, l0 may be assumed as 8 O for HYSD bars ( usually end anchorage is not provided ) and 12 O for mild steel ( U hook is provided usually whose anchorage length is 16 O.Ĭheck for development length IS 456-2000 clause 26.2.1 Development length of bars Ld = O σs / 4 x ‫ﺡ‬bd IS 456-200 clause 26.2.1.1 Table 7-5 Design bond stress (‫ﺡ‬bd ) for plain bars in tensionġ.2 1.4 1.5 1.7 1.9 Note-1 : ‫ﺡ‬bd shall be increased by 25 % for bars in compression Note-2 : In case of deformed bars confirming to IS : 1786-1985, the value of ‫ﺡ‬bd shall be increased by 60 %. b ) Maximum reinforcement - The maximum area of tension reinforcement shall not exceed 0.04 b D. Structural Members 26.5.1 Beams 26.5.1.1 Tension Reinforcement a ) Minimum reinforcement - The minimum area of tension reinforcement shall not be less than that given by the following : As / b d = 0.85 / fy where, As = minimum area of tension reinforcement, b = breadth of the beam or the breadth of the web of T- beam, d = effective depth, and fy = characteristic strength of reinforcement in N / mm 2. 0.084 IS 456-2000 Clause 26.5 Requirements of Reinforcement for Table 6-4 Limiting Percentage of Reinforcement Pt,limįor singly reinforced rectangular sections fck N 2 / mm Table 6-3 Limiting Moment of resistance factor Q lim, N / mm2 For singly reinforced rectangular sections Index for Singly Reinforced Rectangular Sections

If Xu Xu,max the section is over-reinforced ( doubly reinforced ) where, Xu,max = 0.53 x d ( for Fe250 mild steel ) Xu,max = 0.48 x d ( for Fe415 HYSD steel ) Xu,max = 0.46 x d ( for Fe500 HYSD steel ) Xu,max = 0.44 x d ( for Fe550 HYSD steel ) Xu =( 0.87 fy Ast ) / ( 0.36 fck b ) Table 6-2 Limiting Moment of Resistance and Reinforcement Ast,lim = Mu,lim / ( 0.87 fy ( d - 0.42 Xu,max ) ) Asc = Mu2 / ( fsc x ( d - d' ) ) Ast2 = Asc fsc / 0.87 fy Ast = Ast,lim + Ast2. Design of Rectangular water tank CASE-1 ( L / B Mu,lim : design the section either increasing the dimensions of section or d Over reinforced section ( doubly-reinforced beam ).The additional moment of resist needed is obtained by providing compression( top ) reinforcement and additional te reinforcement.

Design of rectangular tanks pdf to excel